Steelers quarterback Ben Roethlisberger was named AFC Offensive Player of the Week for his performance versus the Baltimore Ravens in Week 9, the NFL announced today.
After being honored for the same award for his historical performance in Week 8 against the Colts, Roethlisberger completed 25-of-37 passes for 340 yards with six touchdowns and zero interceptions versus the Ravens.
Over the past two weeks, Roethlisberger has completed 65-of-86 passes (75.6 percent) for 862 yards with 12 touchdowns and zero interceptions. He set an NFL record by throwing the most touchdowns in a two-game span (12).
This marks the 11th time that Roethlisberger has been named AFC Offensive Player of the Week, the first time he has been honored in consecutive weeks and the third time he has won the award multiple times in a season (Weeks 5 and 8 in 2011, Weeks 10 and 16 in 2007).
