Steelers quarterback Ben Roethlisbergerwas named AFC Offensive Player of the Week after leading his team to a 25-17 victory over the New England Patriots. It marks the second time Roethlisberger has won the award this season, including twice in the month of October, and the eighth time he has been honored with this award in his career.
Roethlisberger finished 36-of-50 for a season-high 365 yards and two touchdowns against the Patriots, recording his third 300-yard game of the season and the 18th of his career. His 36 completions and 50 pass attempts were the second-most of his career.
Roethlisberger set career highs with 23 completions and 32 pass attempts in the first half, and he went 9-for-12 for 104 yards with one touchdown on third-down pass plays. Roethlisberger has now thrown for at least 200 yards in career-best 16 straight regular-season games.
